What will be the output of the following code? void main (){ int i = 0 , a[3] ; a[i] = i++; printf ("%d",a[i]) ; }

What will be the output of the following code? void main (){ int i = 0 , a[3] ; a[i] = i++; printf ("%d",a[i]) ; }

 The output for the above code would be a garbage value. In the statement a[i] = i++; the value of the variable i would get assigned first to a[i] i.e. a[0] and then the value of i would get incremented by 1. Since a[i] i.e. a[1] has not been initialized, a[i] will have a garbage value. 

By:Umang
Date:2001-01-09 00:00:00

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