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A current of – 8 + 6sqrt{2} (sin (ωt + 30°)) A is passed through three meters. The respective readings (in ampere) will be?
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Question: A current of – 8 + 6sqrt{2} (sin (ωt + 30°)) A is passed through three meters. The respective readings (in ampere) will be?
1.8, 6 and 10
2.8, 6 and 8
3.– 8, 10 and 10
4.-8, 2 and 2
Show Answer
Answer:3
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